因式分解:x 3+y ,因式分解: x^3+y^3=?

2020-11-24 19:43:26 字数 2706 阅读 8660

1楼:匿名用户

^^^x^3+y^3=(x+y)(x^2-xy+y^2)=(x+y)(x^2-xy+y^2/4+3y^2/4)=(x+y)[(x-y/2)^2-(sqrt(3)yi/2)^2]=(x+y)(x-y/2+sqrt(3)yi/2)(x-y/2-sqrt(3)yi/2)

因式分解(x+y+z)^3-x^3-y^3-z^3

2楼:小贱

^参考下面

(x+y+z)^3-x^3-y^3-z^3=3yx^2+3xy^2+3xz^2+3yz^2+3zx^2+3zy^2+6xyz

=3xy(x+y)+3z^2(x+y)+3z(x^2+y^2+2xy)

=3xy(x+y)+3z^2(x+y)+3z(x+y)^2=3(x+y)[xy+z^2+z(x+y)]=3(x+y)[x(y+z)+z(y+z)]=3(x+y)(x+z)(y+z)、

、好评,,o(∩_∩)o谢谢

x^3+y^3+z^3-3xyz因式分解

3楼:匿名用户

x+y+z-3xyz

=(x+y+z)(x+y+z-xy-xz-yz)

(这用到的是公式a+b+c-3abc=(a+b+c-ab-ac-bc))

4楼:虎慈建萍韵

^^^x^3+y^3+z^3-3xyz

=(x^3+3yx^2+3xy^2+y^3)+z^3-3xyz-3yx^2-3xy^2

=(x+y)^3+z^3-3xy(x+y+z)=(x+y+z)[(x+y)^2-(x+y)z+z^2]-3xy(x+y+z)

=(x+y+z)[(x^2+2xy+y^2-xz-yz+z^2)-2xy]

=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

x^3+3x^2-x-3怎么因式分解?

5楼:从此再努力

x^3+3x^2-x-3=x^2(x+3)-(x+3)=(x^2-1)(x+3)=(x+1)(x-1)(x+3)

6楼:小茗姐姐

x^3+3x^2-x-3

=x(x-1)+3(x-1)

=x(x+1)(x-1)+3(x-1)

=(x-1)(x+x+3)

7楼:线钊示冠

^^立方和公式:a^3+b^3=(a+b)(a^2-ab+b^2)立方差公式:a^3-b^3=(a-b)(a^2+ab+b^2)3x^3+x^2+x-2

=3x^3+x^2+x-2-1+1

=3x^3+x^2+x-3+1

=(3x^3-3)+(x^2+x+1)

=3(x-1)(x^2+x+1)+(x^2+x+1)=(3x-3+1)(x^2+x+1)

=(3x-2)(x^2+x+1)

希望能帮到你,望采纳!!

因式分解:x^2(y+z)+y^2(z+x)+z^2(x+y)-(x^3+y^3+z^3)-2xyz 10

8楼:一朵不知所云

^^^^x^2(y+z)+y^2(z+x)+z^2(x+y)-(x^3+y^3+z^3)-2xyz

=x^2(y+z)+y^2*z+y^2*x+z^2*x+z^2*y-x^3-y^3-z^3-2xyz

=x^2(y+z-x)+x(y^2+z^2-2yz)+(y^2*z+z^2*y-y^3-z^3)

=x^2(y+z-x)+x(y-z)^2+[y^2(z-y)-z^2(z-y)]

=x^2(y+z-x)+x(y-z)^2+(y+z)(y-z)(z-y)

=x^2(y+z-x)+x(y-z)^2-(y+z)(y-z)^2

=x^2(y+z-x)+(y-z)^2(x-y-z)

=(x-y-z)(z-y-x)(z-y+x)

x-y+(y-3)^3因式分解

9楼:翔丶羽

解:x-y+(y-x)

=-(y-x)+(y-x)(x-y)

=(y-x)[(x-y)-1]

=(y-x)(x-2xy+y-1)

化到这步差不多了.

8x^3+27y^3怎么因式分解啊

10楼:寂寂落定

应用立方和公式:a^3+b^3=(a+b)(a^2-ab+b^2)

8x^3+27y^3=(2x)^3+(3y)^3=(2x+3y)(4x^2-6xy+9y^2)

11楼:匿名用户

8x^3+27y^3

=(2x+3y)(4x^2-6xy+9y^2)

公式:a^3+b^3=(a+b)(a^2-ab+b^2)

12楼:左右鱼耳

8x+27y=(2x+3y)(4x-6xy+9y)

(x^3+y^3+z^3-3xyz)怎么因式分解?

13楼:匿名用户

x+y+z-3xyz

=x+3xy+3xy+y+z-3xy-3xy-3xyz=(x+y)+z-3xy(x+y+z)=(x+y+z)(x+2xy+y-xz-yz-3xy)=(x+y+z)(x+y+z-xy-yz-xz)

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